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The Gradient direction and rate of maximum increase

  1. Nov 15, 2011 #1
    1. The problem statement, all variables and given/known data
    What is the direction and rate of maximum increase?
    f(x,y) = x^2 + y^3, v = <4,3>, P = (1,2)


    2. Relevant equations



    3. The attempt at a solution
    The direction should be as same as the gradient so < 2,12>
    The rate of maximum increase is magnitude of the gradient so sqrt(4+144) = sqrt(148).
    Is that right?
     
  2. jcsd
  3. Nov 15, 2011 #2

    LCKurtz

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