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The Gradient direction and rate of maximum increase

  • Thread starter DrunkApple
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  • #1
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Homework Statement


What is the direction and rate of maximum increase?
f(x,y) = x^2 + y^3, v = <4,3>, P = (1,2)


Homework Equations





The Attempt at a Solution


The direction should be as same as the gradient so < 2,12>
The rate of maximum increase is magnitude of the gradient so sqrt(4+144) = sqrt(148).
Is that right?
 

Answers and Replies

  • #2
LCKurtz
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Yes.
 

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