The Gradient direction and rate of maximum increase

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SUMMARY

The discussion focuses on finding the direction and rate of maximum increase for the function f(x,y) = x^2 + y^3 at the point P = (1,2). The gradient is calculated as ∇f = <2, 12>, indicating that the direction of maximum increase aligns with the gradient vector. The rate of maximum increase is determined to be the magnitude of the gradient, calculated as √(4 + 144) = √148, confirming the correctness of the solution.

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Homework Statement


What is the direction and rate of maximum increase?
f(x,y) = x^2 + y^3, v = <4,3>, P = (1,2)


Homework Equations





The Attempt at a Solution


The direction should be as same as the gradient so < 2,12>
The rate of maximum increase is magnitude of the gradient so sqrt(4+144) = sqrt(148).
Is that right?
 
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