- #1
eng_pro
- 7
- 0
Hey, I have this problem where i am trying to find the limit of the equation:
2sin(0.5*n*pi)
---------------
n*pi
when n--->0
I used the l-hospital rule to solve it and got
pi*cos(0.5*n*pi)
---------------- = 1
pi
The answer is supposed to be 0 and using another method it proved so!
So what am i doing wrong
2sin(0.5*n*pi)
---------------
n*pi
when n--->0
I used the l-hospital rule to solve it and got
pi*cos(0.5*n*pi)
---------------- = 1
pi
The answer is supposed to be 0 and using another method it proved so!
So what am i doing wrong