The Integration by Parts Method: How to Integrate x * 5^x

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SUMMARY

The discussion focuses on the integration of the function x * 5^x using the integration by parts method. The participants detail the steps involved, identifying u = x and dv = 5^x, leading to the expression (x/ln5)(5^x) - (5^x/(ln(5)^2)) as the final result, including the constant of integration. The integration by parts formula is explicitly applied, demonstrating the process of breaking down the integral into manageable components.

PREREQUISITES
  • Understanding of integration by parts formula: ∫ f(x)g'(x)dx = f(x)g(x) - ∫ f'(x)g(x)dx
  • Knowledge of exponential functions and their properties, specifically 5^x
  • Familiarity with the natural logarithm, particularly ln(5)
  • Basic differentiation techniques to verify integration results
NEXT STEPS
  • Study the application of integration by parts with different functions
  • Learn about the properties of exponential functions and their integrals
  • Explore advanced integration techniques, such as substitution and partial fractions
  • Practice verifying integration results through differentiation
USEFUL FOR

Students studying calculus, particularly those focusing on integration techniques, as well as educators looking for examples of integration by parts in action.

whatlifeforme
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Homework Statement


integrate by parts.

Integral: x * 5^x

Homework Equations


The Attempt at a Solution


i got to (1/ln5) * 5^x ;; and I'm not sure how to integrate further.
 
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whatlifeforme said:

Homework Statement


integrate by parts.

Integral: x * 5^x

Homework Equations



The Attempt at a Solution


i got to (1/ln5) * 5^x ;; and I'm not sure how to integrate further.
How about giving a few details regarding how you got that answer & where you are in the process of integration by parts.
 
integral (x * 5^x)

u=x; du=dx
dv=5^x ; v=(1/ln5)(5^x)

(x/ln5)5^x - integral ((1/ln5)(5^x) dx)
 
Hi whatlifeforme :)

You have to use the formula:

\int f(x)g'(x)dx = f(x)g(x)-\int f'(x)g(x)dx

In this case

f(x)= x\implies f'(x)= 1

g'(x)= 5^{x}= e^{x\ln(5)}\implies g(x)=\frac{e^{x\ln(5)}}{\ln(5)}= \frac{5^x}{\ln(5)}


so \int f(x)g'(x)dx = f(x)g(x)-\int f'(x)g(x)dx

becomes

\int x 5^x dx = x \frac{5^{x}}{\ln(5)}-\int \frac{5^{x}}{\ln(5)}dx

Now you have to solve

\int \frac{5^x}{\ln(5)}dx= \frac{1}{\ln(5)}\int 5^xdx

;)
 
so would the final simplified answer be:

(x/ln5)(5^x) - (5^x/(ln(5)^2)
 
whatlifeforme said:
so would the final simplified answer be:

(x/ln5)(5^x) - (5^x/(ln(5)^2)

... plus the constant of integration.

Yes.

Check it by differentiating.
 

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