The length element in cylindrical coordinates

Click For Summary
SUMMARY

The discussion focuses on deriving the length element in cylindrical coordinates, specifically showing that \( ds^{2} = d\rho^{2} + \rho^{2} d\theta^{2} + dz^{2} \). The transformation equations \( x = \rho \cos \theta \), \( y = \rho \sin \theta \), and \( z = z \) are utilized to express the Cartesian coordinates in terms of cylindrical coordinates. The participant seeks guidance on applying the chain rule and total derivatives to compute \( ds^{2} \) using the partial derivatives of the coordinates.

PREREQUISITES
  • Understanding of cylindrical coordinates and their transformation to Cartesian coordinates.
  • Familiarity with partial derivatives and the chain rule in multivariable calculus.
  • Knowledge of differential geometry concepts, particularly length elements.
  • Ability to manipulate and differentiate trigonometric functions.
NEXT STEPS
  • Study the application of the chain rule in multivariable calculus.
  • Learn about differential forms and their role in geometry.
  • Explore the derivation of length elements in other coordinate systems, such as spherical coordinates.
  • Practice problems involving transformations between coordinate systems and their implications in calculus.
USEFUL FOR

Students of calculus, particularly those studying multivariable calculus and differential geometry, as well as educators seeking to clarify the concept of length elements in cylindrical coordinates.

stripes
Messages
262
Reaction score
0

Homework Statement



Show that in cylindrical coordinates

x = \rho cos \theta
y = \rho sin \theta
z = z

the length element ds is given by

ds^{2} = dx^{2} + dy^{2} + dz^{2} = d \rho^{2} + \rho^{2} d \theta ^{2} + dz^{2}

Homework Equations



--

The Attempt at a Solution



Notice \rho = \sqrt{x^{2} + y^{2}}

I have found expressions for ∂x/∂θ, ∂x/∂ρ, ∂y/∂θ, ∂y/∂ρ, ∂ρ/∂x, ∂ρ/∂y, ∂θ/∂x, ∂θ/∂y, and of course it is trivial that dz = dz. Given all of these, how do i start using chain rule and total derivatives to find ds2? I guess because i have 8 partials but end up only ρ, θ, and z, i don't really know which ones to start with.

Any help is greatly appreciated.
 
Physics news on Phys.org
stripes said:

Homework Statement



Show that in cylindrical coordinates

x = \rho cos \theta
y = \rho sin \theta
z = z

the length element ds is given by

ds^{2} = dx^{2} + dy^{2} + dz^{2} = d \rho^{2} + \rho^{2} d \theta ^{2} + dz^{2}

Homework Equations



--

The Attempt at a Solution



Notice \rho = \sqrt{x^{2} + y^{2}}

I have found expressions for ∂x/∂θ, ∂x/∂ρ, ∂y/∂θ, ∂y/∂ρ, ∂ρ/∂x, ∂ρ/∂y, ∂θ/∂x, ∂θ/∂y, and of course it is trivial that dz = dz. Given all of these, how do i start using chain rule and total derivatives to find ds2? I guess because i have 8 partials but end up only ρ, θ, and z, i don't really know which ones to start with.

Any help is greatly appreciated.

Start from
<br /> dx = \frac{\partial x}{\partial \rho}d\rho + \frac{\partial x}{\partial \theta}d\theta<br />
Squaring both sides gives dx^2.
 
yeah i got it. thanks.
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
5K
Replies
13
Views
3K
Replies
2
Views
1K
  • · Replies 21 ·
Replies
21
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K