The operator of momentum (layman question)

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The discussion centers on the two forms of the momentum operator in quantum mechanics, specifically represented as p = (ħ/i)(d/dx) and p = -iħ(d/dx). The equivalence of these two expressions is established by multiplying the right-hand side of the first equation by i/i, demonstrating their mathematical consistency. This clarification highlights the importance of understanding operator notation in quantum mechanics.

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paulzhen
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I found two "forms" of it:

p=\frac{\hbar}{i}\frac{d}{dx}

p=-i\hbar\frac{d}{dx}

how could they be the same??
 
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Multiply the right hand side of the first equation with i/i.

Zz.
 
oh...yes thanks a lot
 

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