The operator of momentum (layman question)

[paulzhen]

I found two "forms" of it:

p=\frac{\hbar}{i}\frac{d}{dx}

p=-i\hbar\frac{d}{dx}

how could they be the same??

 

[ZapperZ]

Multiply the right hand side of the first equation with i/i.

Zz.

 

[paulzhen]

oh...yes thanks a lot