The period of water oscillating in a U-tube

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SUMMARY

The discussion centers on the calculation of the period of water oscillating in a U-shaped tube. The professor emphasizes that the effective length of the water column must be greater than the average of the lengths around the inside and outside of the tube. This is crucial as the volume derived from this length is used to compute the kinetic energy of the water, which varies due to differing speeds between the outer and inner water layers. The kinetic energy's dependence on the square of the speed means that simply averaging the lengths does not yield an accurate representation of the system's dynamics.

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In the following lecture (starting at 21:00), the professor says that when predicting the period of water oscillating in a U-shaped tube, that the "length" of the water column that you should use should be greater than the average of the length around the outside and around the inside. Can someone explain this? Thanks.
 
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The length is used to calculate the volume of the water, and the volume is used to calculate the kinetic energy of the water if it's moving with a speed v.

The water on the outside will be moving faster than the water on the inside, and because the kinetic energy depends on the square of the speed, the sum won't add up to the kinetic energy of the water in the middle.
 
willem2 said:
The length is used to calculate the volume of the water, and the volume is used to calculate the kinetic energy of the water if it's moving with a speed v.

The water on the outside will be moving faster than the water on the inside, and because the kinetic energy depends on the square of the speed, the sum won't add up to the kinetic energy of the water in the middle.
Great explanation. Thanks.
 

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