The Rayleigh-Plesset Equation for Sonoluminescence

  • Thread starter Thread starter Ashiataka
  • Start date Start date
  • Tags Tags
    Sonoluminescence
AI Thread Summary
The discussion focuses on sonoluminescence and the application of the Rayleigh-Plesset equation to understand the phenomenon. The user is exploring the relationship between various pressure terms in the equation and their implications for the behavior of the bubble involved in sonoluminescence. They seek clarification on the significance of the gas pressure (pg) and the presence of a density factor in the rearranged equation. Additionally, a user shares their success in capturing a faint green streak during a long exposure, highlighting the aesthetic aspect of the phenomenon. The conversation reflects both a scientific inquiry and an appreciation for the visual effects of sonoluminescence.
Ashiataka
Messages
21
Reaction score
1
I'm investigating the phenomenon of sonoluminescence. A quick search has yielded the Rayleigh-Plesset equation as being of use.
\frac{P_B(t)-P_\infty(t)}{\rho_L}=R\frac{d^2R}{dt^2}+\frac{3}{2}\left( \frac{dR}{dt}\right)^2+\frac{4\nu_L}{R}\frac{dR}{dt}+\frac{2S}{\rho_LR}

A brief look on the wikipedia entry on sonoluminescence yields an approximate form.
R\frac{d^2R}{dt^2} + \frac{3}{2}\left( \frac{dR}{dt}\right)^2 = \frac{1}{\rho}\left(p_g - P_0 - P(t) - \frac{4\nu_L}{R} \frac{dR}{dt} - \frac{2S}{R}\right)

Now I'm assuming that P0 = PB and P = Pinfinite. So that gives (when rearranged):

\frac{P_B(t) + P_\infty(t)}{\rho_L} + R\frac{d^2R}{dt^2} + \frac{3}{2}\left( \frac{dR}{dt}\right)^2 + \frac{2S}{\rho_LR} = \frac{p_g }{\rho_L}-\frac{4\nu_L}{\rho_LR} \frac{dR}{dt}

which has the two terms on the RHS being different from the original expression. Firstly, what is pg? And secondly, why do both terms now have a 1/rho factor?

Thank you.
 
Physics news on Phys.org
Thank you.

I've managed to get a very faint green streak on a long exposure. It's quite a lovely effect.
 
Thread 'Question about pressure of a liquid'
I am looking at pressure in liquids and I am testing my idea. The vertical tube is 100m, the contraption is filled with water. The vertical tube is very thin(maybe 1mm^2 cross section). The area of the base is ~100m^2. Will he top half be launched in the air if suddenly it cracked?- assuming its light enough. I want to test my idea that if I had a thin long ruber tube that I lifted up, then the pressure at "red lines" will be high and that the $force = pressure * area$ would be massive...
I feel it should be solvable we just need to find a perfect pattern, and there will be a general pattern since the forces acting are based on a single function, so..... you can't actually say it is unsolvable right? Cause imaging 3 bodies actually existed somwhere in this universe then nature isn't gonna wait till we predict it! And yea I have checked in many places that tiny changes cause large changes so it becomes chaos........ but still I just can't accept that it is impossible to solve...

Similar threads

Replies
1
Views
2K
Replies
7
Views
1K
Replies
4
Views
2K
Replies
8
Views
199
Replies
5
Views
1K
Back
Top