The relation between impulse and momentum

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SUMMARY

The relationship between impulse and momentum is defined by the equation I=FΔt, where impulse (I) is equal to the change in momentum (ΔP) caused by a net force (F) acting over a time interval (Δt). This relationship holds true for both constant and variable forces, as demonstrated by the integral form of the equation. A resultant force applied over a longer duration results in a greater change in momentum, while a smaller force applied for an extended time can produce the same impulse as a larger force applied briefly. Understanding these concepts is crucial for grasping fundamental physics principles.

PREREQUISITES
  • Understanding of Newton's Second Law of Motion
  • Basic knowledge of calculus, specifically integrals
  • Familiarity with the concepts of force and acceleration
  • Knowledge of units related to impulse and momentum
NEXT STEPS
  • Study the derivation of impulse-momentum theorem in detail
  • Learn about the applications of impulse in real-world scenarios
  • Explore the relationship between impulse and energy transfer
  • Investigate the units of impulse and momentum in different measurement systems
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Students of physics, educators teaching mechanics, and anyone interested in understanding the fundamental principles of motion and force interactions.

greg_rack
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I get that the impulse is I=FΔt, but why is it even equal to change in momentum caused by the force under consideration?
 
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$$\vec{I} = \int_{t_1}^{t_2} \vec{F} dt = \int_{t_1}^{t_2} \frac{d\vec{P}}{dt} dt = \vec{P}(t_2) - \vec{P}(t_1) = \Delta \vec{P}$$##\vec{F}## is the net force on the particle or extended body.
 
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etotheipi said:
$$I = \int_{t_1}^{t_2} \vec{F} \cdot dt = \int_{t_1}^{t_2} \frac{d\vec{P}}{dt} dt = \vec{P}(t_2) - \vec{P}(t_1) = \Delta \vec{P}$$##\vec{F}## is the net force on the particle or extended body.
I still haven't studied integrals... 😅
 
For constant ##\vec{F}##,$$\vec{I} = \vec{F} \Delta t = \frac{d\vec{P}}{dt} \Delta t = \Delta \vec{P}$$
 
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etotheipi said:
For constant ##\vec{F}##,$$I = \vec{F} \Delta t = \frac{d\vec{P}}{dt} \Delta t = \Delta \vec{P}$$
Thank you so much, now it's clear!
 
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greg_rack said:
Summary:: I've studied momentum and impulse a long time ago, don't judge the silliness of this question

I get that the impulse is I=FΔt, but why is it even equal to change in momentum caused by the force under consideration?
Please, see:
https://en.m.wikipedia.org/wiki/Impulse_(physics)

https://en.m.wikipedia.org/wiki/Momentum

"A resultant force causes acceleration and a change in the velocity of the body for as long as it acts. A resultant force applied over a longer time therefore produces a bigger change in linear momentum than the same force applied briefly: the change in momentum is equal to the product of the average force and duration. Conversely, a small force applied for a long time produces the same change in momentum—the same impulse—as a larger force applied briefly."
 
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Lnewqban said:
Please, see:
https://en.m.wikipedia.org/wiki/Impulse_(physics)

https://en.m.wikipedia.org/wiki/Momentum

"A resultant force causes acceleration and a change in the velocity of the body for as long as it acts. A resultant force applied over a longer time therefore produces a bigger change in linear momentum than the same force applied briefly: the change in momentum is equal to the product of the average force and duration. Conversely, a small force applied for a long time produces the same change in momentum—the same impulse—as a larger force applied briefly."
Really exhaustive explanation, thank you!
 
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You are welcome. :smile:
These basic concepts are very important.
Note units related to impulse and momentum in each system.
 
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