The second shifting theorem and the unit step function

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SUMMARY

The discussion focuses on applying the second shifting theorem to find the Laplace transform of the piecewise function defined as f(t) = t² for t < 4 and f(t) = t for t ≥ 4. The correct expression using the unit step function is f(t) = t²(1 - u(t - 4)) + tu(t - 4). Participants clarify that the second shifting theorem allows for the transition from t² to t at t = 4 by incorporating the term u(t - 4)(-t² + t) to adjust the function accordingly.

PREREQUISITES
  • Understanding of Laplace transforms
  • Familiarity with the second shifting theorem
  • Knowledge of the unit step function, u(t)
  • Basic calculus, particularly piecewise functions
NEXT STEPS
  • Study the application of the second shifting theorem in various contexts
  • Learn how to derive Laplace transforms for piecewise functions
  • Explore advanced properties of the unit step function
  • Practice solving problems involving Laplace transforms and shifting theorems
USEFUL FOR

Students preparing for exams in differential equations, engineers, and mathematicians focusing on Laplace transforms and their applications in control systems and signal processing.

Rubik
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Homework Statement



I am trying to do some revision for an upcoming exam and one question I am trying to figure out is

Use the second shifting theorem to find the Laplace transfrom of the following function:
f(t) = t2, t < 4
t, t ≥ 4

Homework Equations





The Attempt at a Solution


I just don't understand how to get from the question to
f(t) = t2[1 - u(t-4)] + tu(t-4)
I am really struggling with applying the second shifting theorem to express in terms of the unit step function I am failing to see how it works because nothing is explained in basic detail?
 
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Rubik said:

Homework Statement



I am trying to do some revision for an upcoming exam and one question I am trying to figure out is

Use the second shifting theorem to find the Laplace transfrom of the following function:
f(t) = t2, t < 4
t, t ≥ 4

Homework Equations





The Attempt at a Solution


I just don't understand how to get from the question to
f(t) = t2[1 - u(t-4)] + tu(t-4)
I am really struggling with applying the second shifting theorem to express in terms of the unit step function I am failing to see how it works because nothing is explained in basic detail?

Think of it this way. You start out with f(t) = t2. Then at t = 4 you want to take out the t2 and put in t, so you add the term u(t-4)(-t2+t).

Then put it all together:

f(t) = t2+u(t-4)(-t2+t)

Now, if you wish, you can collect terms on the various powers of t:

f(t) = t2(1-u(t-4)) + tu(t-4)
 

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