The speed of a car with constant acceleration

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SUMMARY

The discussion focuses on calculating the average acceleration of a sports car that accelerates from 48.3 km/h to 80.5 km/h in 3.7 seconds. The correct average acceleration is derived using the formula a = dv/dt, with proper unit conversions from km/h to m/s. The final calculated acceleration is approximately 11.0 m/s², not 145 m/s² as initially stated. For part (b), participants are advised to use the kinematic equation to determine the speed after an additional second, incorporating the previously calculated acceleration.

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Homework Statement


A sports car accelerates in third gear from 48.3 km/h to 80.5 hm/h in 3.7 seconds. (a)What is the average acceleration of this car in m/s^2? (b) If the car maintained this acceleration, how fast would it be moving one second later?


Homework Equations



a= dv/dt
1km = 1000 m
1 h = 60s

The Attempt at a Solution


(a) I did 48.3 km/h to 805 m/s and 80.5 km/h to 4025/3 m/s; plugged them into the a formula-> (4025-(805)3)/3 which gives you (1610/3)/3.7 (since 3.7 is delta t), and my final answer 145 m/s^2.

(b) This is the part I'm having trouble with, do I just use 4.7 instead of 3.7 for t?
 
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1 h is not 60s. 1 minute is 60s.

For part (a) you should check your conversions from km/hr to m/s. Can you show your work?

For part (b) you should state a kinematic formula that is applicable, and yes, you'd then use 4.7s in that formula (along with the acceleration that you calculate in part (a)).
 

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