The total system momentum vector before the collision is approximately

AI Thread Summary
In the discussion about the total system momentum vector before a collision between two cars, Car X moves east at 1.000 m/s and Car Y moves north at the same speed. Each car has a mass of 1000 kg, leading to individual momenta of 1000 kg·m/s in their respective directions. The total momentum vector is calculated using the Pythagorean theorem, resulting in approximately 1414 kg·m/s directed toward the northeast. The confusion arises from the need to visualize the vector sum, which combines the eastward and northward momentum. Understanding this vector addition is crucial for grasping the concept of momentum in collisions.
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Envision a minor motor-vehicle accident. Car X backs out of a parking space at 1.000m/s toward the east. Car Y, whose driver searches for a place to park, travels north at 1.000m/s. Neither driver sees the other car, and the cars collide. Suppose that each car (including its driver) has a mass of 1000kg. The total system momentum vector before the collision is approximately?

a) 1000kg x m/s toward the northeast.
b) 1414 kg x m/s toward the northeast.
c) 2000kg x m/s toward the northeast.
d) zero, because the vehicles haven't hit each other yet!

It is said to be answer b, but I'm not sure how the textbook arrived at this conclusion.
Please help!
 
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Okay so draw a vector sum. Draw at arrow going east for X and an arrow going north for Y, find each of their momentums and ... Hint: triangles
 


I haven't been taught to use triangles yet. So I'm a bit confused. I know that it involves pythagoras therom and i got the answer of 1414, but I'm not sure how it fits in.
 
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