The truck, the box and the slide

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    Box Slide Truck
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Homework Help Overview

The discussion revolves around a physics problem involving a truck, a box, and a slide. Participants are exploring concepts related to motion, acceleration, and friction, particularly focusing on the conditions under which the box will slide off the truck.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • The original poster expresses difficulty in solving the problem and seeks input on their progress. Participants inquire about the maximum acceleration of the box and its movement relative to the ground, suggesting a focus on Newton's laws and the effects of friction.

Discussion Status

Participants are actively discussing the problem, with some providing hints and guidance while others share external resources. There is an acknowledgment of differing interpretations of the problem, and while some guidance has been offered, no consensus has been reached on the solution.

Contextual Notes

The original poster mentions receiving an incorrect answer from another source, indicating a potential misunderstanding or miscommunication regarding the problem's requirements. There is also a suggestion that the original poster should focus on their own reasoning rather than seeking direct answers.

yoyobarn
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problem is attached as image...

i asked on yahoo answers, received a reply but is wrong...

it is very challenging (in my opinion)..
I spent over an hour without reaching even a wrong option..
 

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What do you think? Show what you've done so far.

Hints: What's the maximum acceleration of the box? Figure out how far the box moves with respect to the ground.
 
http://answers.yahoo.com/question/i...nkoSvGAazKIX;_ylv=3?qid=20090925002613AAbpiRt

Dr D's answer is correct:

The block will slide once the deceleration of the truck exceeds μg.
Once the block begins to slide, its absolute deceleration is constant at μg.
So the stopping distance of the block is v^2 / (2μg) = 40.77 m.

And the block is allowed to stop within 3 m more than the truck. So the minimum stopping distance of the truck is 37.77 m.

If you use g = 9.81, you get 37.77 m
If g = 10, then you get 37 m.

but his answer is a bit short, and hard to understand...
 
yoyobarn said:
but his answer is a bit short, and hard to understand...
Rather than hunting for answers, your time might be better spent trying to figure it out on your own. Use the hints I gave and your knowledge of Newton's laws.
 

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