The work done by an adiabatic process?

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SUMMARY

The discussion focuses on the work done by an adiabatic process, specifically using the formula W=(C/1-y)(Vf^(1-y)-Vi^(1-y)), where y is defined as Cp/Cv. The variable C is clarified to represent a constant K, typically expressed as PV^γ = K. Participants confirm that during an adiabatic process, the relationship P1V1^γ = P2V2^γ holds, and the ideal gas law cannot be applied in the same manner due to the nature of adiabatic conditions.

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  • Understanding of thermodynamic processes, specifically adiabatic processes.
  • Familiarity with the ideal gas law (PV=nRT).
  • Knowledge of specific heat capacities (Cp and Cv).
  • Basic algebra and manipulation of equations involving exponents.
NEXT STEPS
  • Study the derivation and applications of the adiabatic process equations.
  • Learn about the differences between reversible and irreversible adiabatic processes.
  • Explore the implications of the first law of thermodynamics in adiabatic conditions.
  • Investigate the relationship between temperature, pressure, and volume in adiabatic processes using real gas behavior.
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Students of thermodynamics, mechanical engineers, and anyone studying the principles of heat transfer and energy conservation in adiabatic processes.

JustinLiang
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Homework Statement


On my formula sheet I have this:
W=(C/1-y)(Vf^(1-y)-Vi^(1-y))
y=Cp/Cv

Homework Equations





The Attempt at a Solution



I am confused about what the C in C/1-y stands for. My textbook does not even have this formula and I realized that C is not Cp or Cv...
 
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JustinLiang said:

Homework Statement


On my formula sheet I have this:
W=(C/1-y)(Vf^(1-y)-Vi^(1-y))
y=Cp/Cv

Homework Equations


The Attempt at a Solution



I am confused about what the C in C/1-y stands for. My textbook does not even have this formula and I realized that C is not Cp or Cv...
The C is usually expressed as K as in: PV^\gamma = K. So it can be written:

W = \frac{P_iV_i^\gamma}{1-\gamma}(V_f^{1-\gamma} - V_i^{1-\gamma})

AM
 
Andrew Mason said:
The C is usually expressed as K as in: PV^\gamma = K. So it can be written:

W = \frac{P_iV_i^\gamma}{1-\gamma}(V_f^{1-\gamma} - V_i^{1-\gamma})

AM

Ahh ok thanks! But why is it Vi and Pi, why not Vf and Pf? Is there a reason?
 
JustinLiang said:
Ahh ok thanks! But why is it Vi and Pi, why not Vf and Pf? Is there a reason?
You can make it Vf and Pf or any V, P during the adiabatic process if you like:

P_iV_i^\gamma = P_fV_f^\gamma = PV^\gamma = K = \text{ constant}

AM
 
Andrew Mason said:
You can make it Vf and Pf or any V, P during the adiabatic process if you like:

P_iV_i^\gamma = P_fV_f^\gamma = PV^\gamma = K = \text{ constant}

AM

Okay, so for an adiabatic process, we cannot use the typical ideal gas law P1V1=P2V2 right?

What about PV/T=PV/T?
 
JustinLiang said:
Okay, so for an adiabatic process, we cannot use the typical ideal gas law P1V1=P2V2 right?

What about PV/T=PV/T?
If PV=nRT and PV = constant then T would be constant (assuming n is constant). But in an adiabatic process that does work this cannot be the case: dQ = 0 -> dU = -dW where dW is the work done by the gas. So P1V1 ≠ P2V2.

In a reversible adiabatic process involving an ideal gas, the condition PV^\gamma = K holds. But so does PV=nRT. Substituting P = nRT/V the adiabatic condition becomes:

PV^\gamma = nRTV^{\gamma-1} = K

and since n and R are constant (assuming no change in the amount of gas) we have:

TV^{\gamma-1} = K/nR = K' = \text{constant} and

PV/T = nR = \text{constant}

AM
 

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