- #36

Chestermiller

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- Thread starter so_gr_lo
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- #36

Chestermiller

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- #37

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Ehm, is it ok to say that the ##dU## of piston is just ##CdT##?

That leads to a nice and neat separable ODE btw, we can find T(V) relatively easily...

- #38

Chestermiller

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Sure. It is considered an incompressible solid.Ehm, is it ok to say that the ##dU## of piston is just ##CdT##?

- #39

TSny

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Yes. This leads to a very simple result for the work done on the gas during the process in terms of the overall temperature change ##\Delta T## for the process. Maybe this is what they want. So, perhaps ##dT## in the statement of the problem is meant to be ##\Delta T##. I don't know.we have: $$dU=(nC_v+C)dT=-PdV=-\frac{nRT}{V}dV$$

You can also use Chestermiller's equations to derive the relation between ##T## and ##V## during the process. Then you can express the work done on the gas in terms of the initial temperature and the initial and final volumes of the gas. This is what I had in mind in post #17.

- #40

so_gr_lo

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