Theodore K's question at Yahoo Answers (Radius of convergence)

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SUMMARY

The discussion focuses on determining the radius of convergence for the power series defined by the expression (-1)^n * (x^(3n)) / ((2n)!) from n=0 to infinity. The ratio test is applied effectively, leading to the conclusion that the limit of the ratio of consecutive terms approaches zero for all real numbers x. Consequently, the radius of convergence is established as R=+\infty, indicating that the series converges for all x in the real number set.

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Fernando Revilla
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Here is the question:

How do i begin to solve for the Radius of convergence and Interval of this series? I know I should be using either the ratio test or root test for this problem :

(-1)^n * (x^(3n)) / ((2n)!) from n=0 to inf

Here is a link to the question:

Calculus Power Series/Radius of Convergence/Interval of Convergence Question? - Yahoo! Answers

I have posted a link there to this topic so the OP can find my response.
 
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Hello Theodore K,

The ratio test works well here $$\lim_{n\to +\infty}\left|\frac{u_{n+1}}{u_n}\right|=\lim_{n \to +\infty}\left|\frac{(-1)^{n+1}x^{3n+3}}{(2n+2)!}\cdot\frac{(2n)!}{(-1)^nx^{3n}}\right|=\\\lim_{n\to +\infty}\left|\frac{x^{3}}{(2n+2)(2n+1)}\right|=0<1\; (\forall x\in\mathbb{R})$$ This implies that the radius of convergence is $R=+\infty$.
 

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