MHB Theodore K's question at Yahoo Answers (Radius of convergence)

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The discussion addresses how to determine the radius of convergence for the series given by (-1)^n * (x^(3n)) / ((2n)!). The ratio test is recommended for this problem, leading to the calculation of the limit as n approaches infinity. The limit simplifies to |x^3| / ((2n+2)(2n+1)), which approaches 0 for all real x. This indicates that the series converges for all x, resulting in an infinite radius of convergence, R = +∞. The conclusion is that the series converges for any real number x.
Fernando Revilla
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Here is the question:

How do i begin to solve for the Radius of convergence and Interval of this series? I know I should be using either the ratio test or root test for this problem :

(-1)^n * (x^(3n)) / ((2n)!) from n=0 to inf

Here is a link to the question:

Calculus Power Series/Radius of Convergence/Interval of Convergence Question? - Yahoo! Answers

I have posted a link there to this topic so the OP can find my response.
 
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Hello Theodore K,

The ratio test works well here $$\lim_{n\to +\infty}\left|\frac{u_{n+1}}{u_n}\right|=\lim_{n \to +\infty}\left|\frac{(-1)^{n+1}x^{3n+3}}{(2n+2)!}\cdot\frac{(2n)!}{(-1)^nx^{3n}}\right|=\\\lim_{n\to +\infty}\left|\frac{x^{3}}{(2n+2)(2n+1)}\right|=0<1\; (\forall x\in\mathbb{R})$$ This implies that the radius of convergence is $R=+\infty$.
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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