Thermal Dynamics Homework: Calculate \Delta V_{Hg}

[Abarak]

Homework Statement

A glass flask whose volume is 1000cm^{3} at a temperature of 0.00*10^0 Celsius is completely filled with mercury at the same temperature. When the flask and mercury are warmed together to a temperature of 52 Celsius, a volume of 8.35cm^{3} of mercury overflows the flask.

the coefficient of volume expansion of mercury is \beta_{Hg} = 1.80*10^{-4}K

Problem:
Calculate the change in volume of the mercury \Delta V_{Hg} during heating.

Homework Equations

\Delta T = T_f - T_i
\Delta V = \beta V_o \Delta T

The Attempt at a Solution

\Delta T = 325.15K - 273.15K
\Delta T = 52K

\Delta V_{Hg} = (1.80*10^{-4})(1000)(52)
\Delta V_{Hg} = 7.8 cm^3

I think I am doing this right but the program keeps saying it's wrong.

Any ideas?

-- Abarak

 

[Abarak]

Never mind, I calculated the last equation wrong.

Thanks anyways!

-- Abarak