Thermal energy/ heat in a parallel connection

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SUMMARY

In a parallel connection of resistors, the power (W) generated is directly related to the current flowing through each resistor. For resistors R1 (5 Ohm) and R2 (10 Ohm), the power ratio W1 to W2 is 2:1, as the current through R1 is double that of R2. The formulas used to derive this include W = VI and W = I²R, with the understanding that voltage remains constant across parallel resistors. If the resistors were in series, the power ratio would change to 1:2.

PREREQUISITES
  • Understanding of Ohm's Law (V = IR)
  • Familiarity with power calculations in electrical circuits (P = IV)
  • Knowledge of resistor configurations (series vs. parallel)
  • Basic algebra for manipulating equations
NEXT STEPS
  • Study the implications of resistor configurations on power distribution
  • Learn about Kirchhoff's laws for circuit analysis
  • Explore the concept of equivalent resistance in parallel circuits
  • Investigate thermal energy generation in electrical components
USEFUL FOR

Electrical engineers, physics students, and anyone interested in understanding power distribution in electrical circuits.

AnneX
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Homework Statement
Nope, I am studying for a quiz
Relevant Equations
Not sure, but R and W could be directly proportional...
In a parallel connection heat is produced.

R1 = 5 Ohm

R2 = 10 Ohm

What is the relation of W1/W2?
1:4

1:2

2:1

1:8

3:1

I’d tend to say 1:2, but I am not really sure…
 
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Whats the formula for W? (When you know R and you know something else because they are in parallel.)
 
The current flowing through R1 is double the current flowing through R2
 
Do you know any formula for the heat generated W in a resistance R when a current I flows and there is a pd of V across it?
 
Or, actually, you've <nearly> solved it with your correct answer ##I_1 = 2 I_2##

Edited in <>
 
Do you know
Power=Voltage x Current ##W=VI##
Voltage = Current x Resistance ##V=IR##
So ## W= VI \ = \ IR I \ = \ I^2R##
or ## I = \frac{V}{R} ##
So ## W= VI \ = \ V \frac{V}{R} \ = \ \frac{V^2}{R} ##
 
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E15FD6B3-C293-4534-B6B6-92185C513A2D.jpeg
So, it is 2:1?
 
Yes.
You can always put some numbers in, as you do here, but the formulae are useful to remember.

Important thing here is, to know that the voltage is the same across both, when they in parallel.
So P=IV tells you that power is proportional to current. Current 2:1 so power 2:1

If they were in series, the current would be the same. If you work out the voltages,
P=IV tells you the power is proportional to the voltage for the same current.
 
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Thanks for the help 👍
One more question though, if the two resistors were in series would it be W1 : W2 = 1:2
 
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AnneX said:
One more question though, if the two resistors were in series would it be W1 : W2 = 1:2
Yes.
 
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