Thermal Expansion of brass rod

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SUMMARY

The discussion focuses on calculating the thermal expansion of a brass rod when measured with a steel tape at varying temperatures. The coefficient of linear expansion for brass is 19e-6, while for steel, it is 11e-6. The student correctly applies the formula ΔL = a * L * ΔT, ensuring to use a negative value for ΔL due to the decrease in temperature from 20.0°C to -18.0°C. This approach accurately determines the adjusted length of the brass rod under the specified conditions.

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  • Understanding of thermal expansion concepts
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  • Proficiency in algebraic manipulation of equations
  • Basic knowledge of temperature measurement and conversion
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lackos
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Homework Statement


A student measures the length of a brass rod with a steel tape at 20.0°C. The reading is 80.00 cm. What will the tape indicate for the length of the rod when the rod and the tape are at each of the following temperatures?
a) -18.0°C



Homework Equations


(delta)L=a*L*(delta)T.where a for brass is 19e-6, and steel is 11e-6


The Attempt at a Solution


i sarted by finding the change in the increment of a cm on the steel tape using the the above equation and then finding the expansion for a cm of brass at the temperature. multipplied it by the original measurement, then added the resulting value to the measuremnt. however I am not sure if this is right
 
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Yes that would be correct. Just make sure your value for ΔL is negative, since your change in temperature is negative.
 

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