Thermal Expansion of copper sphere Problem

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SUMMARY

The thermal expansion problem involves a copper sphere with an initial radius of 2.000 cm placed over a hole of radius 1.990 cm in an aluminum plate at 20 degrees Celsius. The common temperature at which the sphere will pass through the hole is determined to be 747 degrees Celsius. The solution requires finding the final radius of the copper sphere, which can be calculated using the thermal expansion formula, Δr = kcopperΔT, where k represents the thermal expansion coefficient. By setting up equations for both the copper and aluminum, one can solve for the final radius and temperature.

PREREQUISITES
  • Understanding of thermal expansion principles
  • Familiarity with the thermal expansion coefficients of copper and aluminum
  • Basic algebra for solving equations
  • Knowledge of temperature conversion and measurement
NEXT STEPS
  • Research the thermal expansion coefficient values for copper and aluminum
  • Learn how to derive and apply the thermal expansion formula in practical scenarios
  • Explore examples of thermal expansion problems involving different materials
  • Study the relationship between temperature and material properties in engineering contexts
USEFUL FOR

Students in physics or engineering, materials scientists, and anyone interested in understanding thermal expansion and its applications in real-world scenarios.

acgold
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This one is giving me trouble because I don't know the final radius and I don't know how to find it.

1. A copper sphere of radius 2.000 cm is placed over a hole of radius 1.990 cm in an aluminum plate at 20 deg. C. At what common temperature will the sphere pass through the hole?
Ans. 747 degrees C

I'm assuming that finding the final radius is the whole point of this problem since once you know the radius the temperature is easy to calculate. Unfortunately I don't know how to find it :confused:
 
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acgold said:
This one is giving me trouble because I don't know the final radius and I don't know how to find it.

1. A copper sphere of radius 2.000 cm is placed over a hole of radius 1.990 cm in an aluminum plate at 20 deg. C. At what common temperature will the sphere pass through the hole?
Ans. 747 degrees C

I'm assuming that finding the final radius is the whole point of this problem since once you know the radius the temperature is easy to calculate. Unfortunately I don't know how to find it :confused:
It falls through when the radii (of the hole and sphere) are equal. I'm guessing there's some formula like \Delta r = k_{copper}\Delta T. Well, it obviously can't be that simple. But you know the initial temperatures and sizes, some sort of constants or material properties for copper and aluminum, and you should be able to express the final size of the copper in terms of the aluminum, or vice versa. That gives you two unknowns (final size and final temperature), and two equations (one for copper one for aluminum), then solve.
 
Man I need to get some sleep or something. The answer was sitting right in front of me. I already had both equations all setup...all I need to do was solve for r and substitute it into the other equation.

Thanks
 

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