Thermal Expansion of Water in glass

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SUMMARY

The discussion focuses on calculating the thermal expansion of water in a glass when the temperature rises from 3°C to 32°C. The volume expansion coefficients used are 28.2e-6/°C for glass and 207.0e-6/°C for water. The user initially calculated the volume increase for water as 1.62177 mL and for glass as 0.208513 mL, leading to a net spill of 1.41325 mL. However, discrepancies in coefficients and potential issues with significant digits or unit requirements may have contributed to the incorrect answer reported by the online assignment system.

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  • Understanding of thermal expansion coefficients
  • Familiarity with the formula V=V0*B*T
  • Knowledge of significant figures in scientific calculations
  • Basic principles of fluid dynamics and volume measurement
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Homework Statement


An ordinary drinking glass is filled to the brim with water (266.3 mL) at 3°C and placed on the sunny pool deck for a swimmer to enjoy. If the temperature of the water rises to 32°C before the swimmer reaches for the glass, how much water will have spilled over the top of the glass?

(Use the following values for the volume expansion coefficients:
For glass 28.2e-6/C and for water 207.0e-6/C)


Homework Equations


V=V0*B*T


The Attempt at a Solution


According to my book, the B for water is 210*10^-6.

I plugged in the values that I have, getting V=266.3*(210*10^-6)*29, and get 1.62177.

I do the same for glass, getting V=266.3*(27*10^-6)*29, and get 0.208513.

I subtract the 0.208513 from 1.62177 and get 1.41325.

What am I doing wrong?
 
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Does anybody know?
 
Why do you think the answer's wrong? It looks right to me.
 
ideasrule said:
Why do you think the answer's wrong? It looks right to me.

The assignment is online and the answer I got comes up as incorrect.
 
That could be due to a lot of reasons. Does the online app care about significant digits? Did it ask for the answer in mL, or in another unit? Is there a standard data table that you're supposed to use? (I notice that the coefficients you used in your problem statement are different from those in your solution.)
 

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