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**[SOLVED] Thermal Stress and a Duel rod of Steel and Al.**

## Homework Statement

A steel rod 0.350 m long and an aluminum rod 0.250 m long, both with the same diameter, are placed end to end between rigid supports with no initial stress in the rods. The temperature of the rods is now raised by 60.0 degrees Celsius.

What is the stress in each rod? (Hint: The length of the combined rod remains the same, but the lengths of the individual rods do not. If the length is permitted to change by an amount [tex]\Delta L[/tex] when its temperature changes by [tex]\Delta T[/tex] the stress is equal to [tex] \frac{F}{A} = Y\left(\frac{\Delta L}{L_0}-\alpha \Delta T\right) [/tex].)

## Homework Equations

[tex] \frac{F}{A} = -Y \alpha \Delta T [/tex]

## The Attempt at a Solution

Not quite sure. Firstly, are they assuming that one bar is conmtracting and the other expanding, if the overall length of the combined bar doesn't change, but the length of each individual rod does?

The question also fails to give the area oif the rod?

TFM