Thermo dynamics, energy calculations in a duct

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SUMMARY

The discussion focuses on energy calculations in a duct carrying a heavy gas, specifically analyzing changes in internal energy, enthalpy, and flow energy. The duct is 5 meters long, inclined at 38 degrees, and transports gas at a mass flow rate of 2 kg/s, with specific heat capacities of Cp = 1105 J/kgK and Cv = 912 J/kgK. Key calculations include determining internal energy (72,960 J), enthalpy (88,400 J), and flow energy (15,440 J), while kinetic energy remains unresolved due to the need for velocity calculations using the ideal gas law.

PREREQUISITES
  • Understanding of thermodynamics principles, specifically energy forms
  • Familiarity with the ideal gas law for density calculations
  • Knowledge of specific heat capacities (Cp and Cv) of gases
  • Basic fluid dynamics concepts, including mass flow rate and velocity
NEXT STEPS
  • Study the ideal gas law and its application in calculating density
  • Learn about energy conservation in thermodynamic systems
  • Explore the relationship between mass flow rate, area, and velocity in fluid dynamics
  • Investigate the calculation of kinetic energy in flowing gases
USEFUL FOR

Students in engineering or physics, particularly those focusing on thermodynamics and fluid mechanics, as well as professionals involved in HVAC systems and energy efficiency analysis.

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Homework Statement



A duct of length 5 m at 38 Degrees inclination to horizon with a cross section dimensions of 0.3 m X 0.4 m is carrying 2 kg/s of a heavy gas at 10C and 1.2 bars and delivers the gas flow at 50C at the end of the duct to a horizontal pipe section. i) Calculate changes to all the individual forms of energy being transported in the DUCT, if Cp and Cv of the gas are 1105 J/kgK and 912 J/kgK. The horizontal section of the pipe is a divergent section with exit cross section area of 0.24 m2. ii) Calculate the mass flow rate at the exit of the divergent pipe and the speed of the flow assuming temperature remains at 50C.

Homework Equations


not a clue


The Attempt at a Solution


found internal energy to be 72960j
found enthalpy to be 88400j
work done or flow energy to be 15440
cant work out kinetic energy as cannot work out the velocity
 
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To get the velocity, set the mass flow equal to rho*A*V where rho is density, A is area, and V is velocity. Determine rho from ideal gas law. The mass flow does not change so the product of rho, A, and V is constant.
 

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