Thermo: Show that the internal energy at constant entropy and volume decrease

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SUMMARY

The discussion focuses on demonstrating that the internal energy (U) decreases during a spontaneous process at constant entropy (S) and volume (V). Utilizing the Helmholtz free energy equation (F = U - TS) and the Clausius inequality (dS - dQ/dT > 0), it is established that for a closed system transitioning from thermodynamic equilibrium state A to state B, the change in internal energy (ΔU) is negative, indicating that Q (heat transfer) is also negative. This confirms that the internal energy decreases in spontaneous processes under the specified conditions.

PREREQUISITES
  • Understanding of thermodynamic concepts such as internal energy, entropy, and free energy.
  • Familiarity with the Clausius inequality and its implications for spontaneous processes.
  • Knowledge of closed systems and thermodynamic equilibrium states.
  • Basic proficiency in calculus for manipulating thermodynamic equations.
NEXT STEPS
  • Study the implications of the Helmholtz free energy in different thermodynamic processes.
  • Explore the relationship between temperature (T) and heat transfer (Q) in varying conditions.
  • Investigate the effects of varying temperature during spontaneous processes on internal energy.
  • Learn about the implications of the second law of thermodynamics in closed systems.
USEFUL FOR

Students and professionals in thermodynamics, particularly those studying physical chemistry or engineering, will benefit from this discussion. It is especially relevant for those analyzing spontaneous processes and internal energy changes in closed systems.

Lagraaaange
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Homework Statement


Show that the internal energy at constant entropy and volume decrease for a spontaneous process

Homework Equations


F = U-TS

The Attempt at a Solution


Use Clausius: dS-dQ/dT > 0
Assume constant volume: TdS > dU
assume constant entropy
this becomes
0>dU

Since dU is negative, Change in F is negative thus spontaneous?
 
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You kind of had the right idea. For a constant volume process that transitions a closed system from thermodynamic equilibrium state A to thermodynamic equilibrium state B, you indicated that:
$$ΔU=Q$$
Also, from the Clausius inequality, for a spontaneous process,

$$ΔS>\frac{Q}{T_B}$$
where TB is the temperature at the heat transfer interface between the system and the surroundings, and where we have assumed that TB is held constant during the spontaneous process. Since ΔS is zero in the transition from state A to state B, we have:

$$0>\frac{Q}{T_B}$$

Therefore, Q<0, and ΔU<0.

I don't know how to do this if TB is varying during the process.
 

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