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## Homework Statement

a beaker contains 200mL of ethyl alcohol at 20degrees. what is the minumum amount of energy that must be removed to produce solid ethyl alcohol..

the melting/freezing pt is 114degrees Lf=1.09x10^5

density is 790kg/m^3

specific heat cap = 2400J/kgK

## Homework Equations

Q=mcdT

Q=ML

m=pv

## The Attempt at a Solution

m=pv=(2.00*10^-4m^3)(790)=0.158kg

Q1=mcdT

=0.158(2400)(94)

=35644.8J

Q2=ML

=0.158(1.09*10^5)

=17222J

Qtotal=Q1+Q2

=52866.8J

i think i did somethign wrong because in the book it says the answer is 68000J can someone help me out i dont know what i did wrong?