Thermodynamics Conceptual Question

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SUMMARY

The discussion focuses on calculating the rate of change in kinetic energy for a fluid system with air flowing through a duct with two inlets and one outlet, under steady-state conditions. The relevant equation for kinetic energy is K.E. = 1/2 mv², where m is the mass flow rate and v is the velocity. The user seeks clarification on how to apply this equation to find the rate of change of kinetic energy between the inlets and the outlet, specifically using the formula d/dt(KE) = 1/2 ̇mv². This indicates a need for understanding the relationship between mass flow rates and velocities at different points in the system.

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Homework Statement



I have a system with air flowing through a ducting with two inlets and one exit operating at steady state. There is no heat transfer or potential energy change. I know the mass flow rates and velocities at all inlets and exits. How would I go about finding the rate of change in kinetic energy for the stream flowing from point 2, an inlet, to point 3, the outlet.

Homework Equations



The Attempt at a Solution



I don't know exactly what the rate of change of kinetic energy between one of the inlets and the exit means, so I don't know where to start.
 
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Maybe the rate of change in the kinetic energies of the inlets and outlet per minute or second? K.E. = \frac{1}{2}mv^2
 
Last edited:
Adding to what crims0ned suggested

\frac{d}{dt}(KE) = \frac{1}{2} \dot{m}v^2
 

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