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Homework Help: Thermodynamics, heat in a copper cube transfer to water

  1. Mar 27, 2010 #1
    1. The problem statement, all variables and given/known data

    When a copper cube of side of 2.0 cm is immersed into a perfectly insulated container filled with 1.0 kg of water at 5 degree celcius , the temperature of water rises to 7 degree celcius . Assuming that no heat is lost to the surrounding , calculate the original temperature of the cube .

    Given density of copper = 8900 kg / m^3 , specific heat capacity of water = 4180 J/kg/K and specific heat capacity of copper = 385 J/kg/K

    2. Relevant equations



    3. The attempt at a solution

    from Q=mc theta = 1(4180)(2) = 8360 J and this is the heat supplied to the water

    mass of copper = (8900)(8 x 10^(-6)) = 0.0712 kg

    8360=0.0712(385) d theta

    d theta = 305 degree celcius but this is the change in temperature , how do i find the original temperature from there .
     
  2. jcsd
  3. Mar 27, 2010 #2

    rl.bhat

    User Avatar
    Homework Helper

    Re: thermodynamics

    Final temperature of the mixture is 7 degrees
    Change in temperature = Original temperature of the copper - final temperature of the mixture.
     
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