When a copper cube of side of 2.0 cm is immersed into a perfectly insulated container filled with 1.0 kg of water at 5 degree celcius , the temperature of water rises to 7 degree celcius . Assuming that no heat is lost to the surrounding , calculate the original temperature of the cube .
Given density of copper = 8900 kg / m^3 , specific heat capacity of water = 4180 J/kg/K and specific heat capacity of copper = 385 J/kg/K
The Attempt at a Solution
from Q=mc theta = 1(4180)(2) = 8360 J and this is the heat supplied to the water
mass of copper = (8900)(8 x 10^(-6)) = 0.0712 kg
8360=0.0712(385) d theta
d theta = 305 degree celcius but this is the change in temperature , how do i find the original temperature from there .