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Thermodynamics Isochoric process .

  1. May 26, 2013 #1
    Hi

    can please check my answer for this question :

    A certain Gas of volume 0.4 m3, pressure of 4.5 bar
    and temperature of 1300 C is heated to in a cylinder to 9 bar when the volume remains
    constant. Calculate

    ¨ (i) Temperature at the
    end of the process,

    ¨ (ii) the heat transferred

    ¨(iii) change in internal energy

    ¨ (iv) work done

    ¨(v) change in enthalpy.

    ¨Assume Cp = 1.005 kJ/kg.K and Cv=
    0.71005 kJ/kg.K


    my answer

    p1v1=mRT

    4.5 X 100 X 0.4 = m X 0.28 X 403

    m= 1595 kg


    now
    i) p2v2 = mRT
    9 X 100 X 0.4 = 1.1595 X 0.28 X T
    T = 806 K

    ii ) the heat transferred
    no heat transferred because the work = 0

    (iii) change in internal energy

    Cv(T2 - T1 )
    0.71005(806 - 40)
    = 54.86

    (iv) work done = 0

    (v) change in enthalpy.
    Cp (T2 - T1 )
    1.005(806 - 40)
    =769.83
     
  2. jcsd
  3. May 28, 2013 #2

    DrClaude

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    Staff: Mentor

    I'll stop you here: what are you doing?
     
  4. May 28, 2013 #3

    SteamKing

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    Staff Emeritus
    Science Advisor
    Homework Helper

    According to you, it is impossible for a stove to heat up a tea kettle because no work is done by the stove.

    Also the OP says the initial temp. is 1300 C, rather than 130 C.
     
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