Thermodynamics proving cp/cv = kt/ks

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SUMMARY

The discussion centers on the derivation of the relationship cp/cv = kt/ks in thermodynamics, specifically through the manipulation of Maxwell's relations. The user presents their equation cp/cv = (dS/dP)T(dP/dT)S / (dS/dV)T(dV/dT)S, which they believe can be transformed into an alternative form. However, the textbook provides a different expression: (dS/dP)T(dV/dS)T / (dV/dT)S(dT/dP)S. The confusion arises from the application of the reciprocal relationship 1/(dX/dY)_Z = (dY/dX)_Z.

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  • Understanding of thermodynamic concepts such as entropy (S), pressure (P), and volume (V).
  • Familiarity with Maxwell's relations and their applications in thermodynamics.
  • Knowledge of partial derivatives and their notation in thermodynamic equations.
  • Basic proficiency in manipulating equations involving thermodynamic identities.
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  • Study the derivation of Maxwell's relations in thermodynamics.
  • Explore the implications of the reciprocal relationship in thermodynamic equations.
  • Investigate the significance of specific heat capacities (cp and cv) in thermodynamic processes.
  • Review advanced thermodynamic identities and their applications in real-world scenarios.
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Chronos000
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Homework Statement



at some point in my derivation I get to the following line:

cp/cv = (dS/dP)T(dP/dT)S / (dS/dV)T(dV/dT)S

I think this equals (dS/dP)T(dS/dV)P / (dP/dT)V(dV/dT)S

- from applying maxwells relations.
but my book says it is in fact the following:

(dS/dP)T(dV/dS)T / (dV/dT)S(dT/dP)S

I haven't a clue how they are doing this
 
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Aren't they just using 1/(dX/dY)_Z=(dY/dX)_Z?
 

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