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## Homework Statement

**figure:**http://www.chegg.com/homework-help/...ivides-p-v-diagram-regions-1-2-follo-q5905441

The dot in Figure (

*b*) represents the initial state of a gas, and the isotherm through the dot divides the

*p*-

*V*diagram into regions 1 and 2. For the following processes, determine whether the change Δ

*E*int in the internal energy of the gas is positive, negative, or zero.

**(a)**the gas moves up along the isotherm

**(b)**the gas moves down along the isotherm

**(c)**the gas moves to anywhere in region 1

**(d)**the gas moves to anywhere in region 2

1.Δ

*E*int is positive

2.Δ

*E*int is negative

3.Δ

*E*int is zero

## Homework Equations

curve of an isotherm is a hyperbola so as the hyperbola becomes closer to the center (0,0) at its inflection point the temperature decreases

deltaE internal= 3/2 nRdelta T means as temperature increases deltaE positive and Vise Versa

## The Attempt at a Solution

when moving on isotherm the delta Einternal will be zero since Einternal depends on the change of temperature the a and b will be zero (a,b =3)

but while moving under the curve then we are getting a lesser temperature. the temperature decreases so delta E negative so c is negative (c= 2

similarly for moving above the curve then d is positive (d=1)

Is my answer correct?

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