Hey I just have a question about regenerator efficiency. I have a problem where the efficiency of the regenerator in a Regenerative Brayton cycle is 0.75, the regenerator takes air in from a compressor which I called h2=636.109 kJ/kg, air then leaves the regenerator and is now at h3=590.1625 kJ/kg. The air then travels through a combustion chamber and then to a turbine. After this the air heads back to the regenerator at an enthalpy of h5=574.847 kJ/kg. Once the air passes through the regenerator is is expelled to the ambient at some T6 and h6. I am thinking if I can find the h6 I can simply interpolate to find T6.
If some of my numbers do not make sense here is the question,
e = regenerator efficiency = 0.75
e = (h6 - h5) / (h6s - h5)
From this website, http://www.mhtl.uwaterloo.ca/courses/me354/lectures/pdffiles/c8.pdf, on page 8 I have used this equation, ( The numbers used in the following equation correspond to the picture here )
e = (h3 - h2) / (h5 - h2)
The Attempt at a Solution
I have already solved the question up to this point but don't know what to do for this part. From the equation above h6s is assuming the system is isentropic and there is no change in enthalpy between the exit and entrance to the regenerator, could I simply use
h2 = h6s
and since I know h2 I can solve for h6 ?