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## Homework Statement

Hey I just have a question about regenerator efficiency. I have a problem where the efficiency of the regenerator in a Regenerative Brayton cycle is 0.75, the regenerator takes air in from a compressor which I called h

_{2}=636.109 kJ/kg, air then leaves the regenerator and is now at h

_{3}=590.1625 kJ/kg. The air then travels through a combustion chamber and then to a turbine. After this the air heads back to the regenerator at an enthalpy of h

_{5}=574.847 kJ/kg. Once the air passes through the regenerator is is expelled to the ambient at some T

_{6}and h

_{6}. I am thinking if I can find the h

_{6}I can simply interpolate to find T

_{6}.

If some of my numbers do not make sense here is the question,

http://imgur.com/dnjS1MF

## Homework Equations

e = regenerator efficiency = 0.75

e = (h

_{6}- h

_{5}) / (h

_{6s}- h

_{5})

From this website, http://www.mhtl.uwaterloo.ca/courses/me354/lectures/pdffiles/c8.pdf, on page 8 I have used this equation, ( The numbers used in the following equation correspond to the picture here )

http://imgur.com/dnjS1MF

e = (h

_{3}- h

_{2}) / (h

_{5}- h

_{2})

## The Attempt at a Solution

I have already solved the question up to this point but don't know what to do for this part. From the equation above h

_{6s}is assuming the system is isentropic and there is no change in enthalpy between the exit and entrance to the regenerator, could I simply use

h

_{2}= h

_{6s}

and since I know h

_{2}I can solve for h

_{6}?

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