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anisha

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## Homework Statement

In an adiabatic steam nozzle,steam is expanded from 10 bar and 473k to an exit pressure of 5 bar.nozzle has an isentropic efficiency of 90%.neglect kinetic energy at the inlet.assuming equilibrium condition at exit,find the velocity of nozzle at exit? given data : i)at nozzle inlet: enthalpy=2828KJ/Kg ; entropy = 6.70KJ/KgK

ii)saturated liquid properties at nozzle exit: enthalpy=640 KJ/Kg;entropy=1.86KJ/KgK

iii)saturated vapour properties at nozzle exit: enthalpy=2750 KJ/Kg;entropy=6.82KJ/KgK

## Homework Equations

energy equation for nozzle: (h1/2)+((c1)^2/2)=(h2/2)+((c2)^2/2)

isentropic efficiency of nozzle : (h1-h2)/(h1-h2s)

where h2s is isentropic enthalpy at nozzle exit

## The Attempt at a Solution

i didn't understand what is the use of giving the efficiency here and how it's related in finding the exit velocity.the isentropic enthalpy i found is h2s=2741.333KJ/Kg,h1=2828KJ/Kg,h2=2750KJ/Kg (given).the correct answer is482 m/s

please do help me ,any hint will be of great use and appreciated!

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