Thermodynamics: two pistons; different pressures, volumes, and temperatures

Click For Summary
SUMMARY

This discussion focuses on the thermodynamic analysis of two insulated vessels containing oxygen at different pressures, volumes, and temperatures. Vessel one has a volume of 15.2 L, pressure of 1.77 atm, and temperature of 280 K, while vessel two has a volume of 23.0 L, pressure of 2.35 atm, and temperature of 460 K. Upon opening the valve connecting the vessels, the final pressure and temperature can be calculated using the equations for an isolated system, specifically applying the first law of thermodynamics and the ideal gas law. The final pressure is derived from the equation P = (P1V1 + P2V2) / (V1 + V2), and the final temperature is determined using the relationship between moles, pressure, volume, and temperature.

PREREQUISITES
  • Understanding of the first law of thermodynamics
  • Familiarity with the ideal gas law
  • Knowledge of diatomic gas properties and internal energy calculations
  • Basic skills in algebra for solving equations
NEXT STEPS
  • Study the first law of thermodynamics in detail
  • Learn about the ideal gas law and its applications
  • Explore the equipartition of energy theorem for diatomic gases
  • Practice solving thermodynamic problems involving multiple gas systems
USEFUL FOR

Students studying thermodynamics, physics enthusiasts, and anyone looking to deepen their understanding of gas behavior in isolated systems.

Color_of_Cyan
Messages
386
Reaction score
0

Homework Statement

20-p-013-alt.gif
Two thermally insulated vessels are connected by a narrow tube fitted with a valve that is initially closed as shown in the figure. One vessel of volume V1 = 15.2 L, contains oxygen at a temperature of T1 = 280 K and a pressure of P1 = 1.77 atm. The other vessel of volume V2 = 23.0 L contains oxygen at a temperature of T2 = 460 K and a pressure of P2 = 2.35 atm. When the valve is opened, the gases in the two vessels mix and the temperature and pressure become uniform throughout.

What is the final temperature?

What is the final pressure?

Homework Equations


I really do not know which are relevantPiVi/ Ti = PfVf/Tf

1 atm = 101325 pa

1L = 1000cm3ΔE internal = Q (isovolumetric process)

ΔE internal = W (adiabatic process)

ΔE internal = Q + W (first law of thermodynamics)

The Attempt at a Solution


I really do not know where to start or what formula to use so any hints would be helpful. We didn't have very much time to cover all this at all (very watered down) so if there is something I am supposed to give and don't give, then sorry.

The way I see it, I think you would solve for the tube as if it were another vessel / piston, but I am not sure how to even do that :(

P1 = 179345 pa
V1 = 152 m3
T1 = 280 kelvins

P2 = 238113 pa
V2 = 230 m3
T2 = 460 kelvins
 
Last edited:
Physics news on Phys.org
as the system is isolated ,its internal energy will remain constant.
oxygen is diatomic, so internal energy of of n moles =2.5nRT=2.5PV
Ei=Ef
Ei=2.5P1V1+2.5P2V2
let final pressure be P,then
Ef=2.5P(v1+V2)
so,P=(P1V1+P2V2)/(V1+V2)

initial moles of oxygen=(P1V1)/RT1 +(P2V2)/RT2
so,P*(V1+V2)=(initial moles)*R*T (T is final temp.)
solve to get,T.
 
Thank you so much. I got them both now even though you practically did the formula for me.

I knew that it was an isolated system too but didn't see how that would help either but...

pcm said:
oxygen is diatomic, so internal energy of of n moles =2.5nRT=2.5PV
Don't know where you got this from. And for temperature, I didn't realize you could use the ideal gas law like that (adding the pressure / volumes of the cylinders equal to find n).Thanks.
 
oxygen is diatomic ,so it has 3 translational and 2 rotational degrees of freedom.
so,internal energy per mole of oxygen is (3+2)/2 *RT ...(equipartition of energy theorem)
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
882
  • · Replies 8 ·
Replies
8
Views
2K
Replies
8
Views
2K
  • · Replies 4 ·
Replies
4
Views
1K
Replies
16
Views
4K
Replies
10
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K