Thermofluids question, saturated water, piston-cylinder.

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The discussion revolves around a thermofluids homework problem involving a piston-cylinder device containing saturated water. The initial state includes a volume of 0.00078539 m^3, quality of 0.85, and pressure of 125 kPa, leading to a calculated initial temperature of approximately 105.97°C and a mass of 0.00067191 kg. After heating, the final state reaches a pressure of 200 kPa and a volume of 0.00157079 m^3, with the conclusion that the substance becomes superheated vapor at around 740°C. The discussion also touches on the uncertainty of determining the state just as the piston hits the stopper, emphasizing the need for more information to accurately assess temperature and pressure. Overall, the analysis highlights the importance of using saturated tables and specific volume calculations in thermodynamic assessments.
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Homework Statement


[/B]
Hi, not sure if I posted this in the correct section... I have a solution, but am unsure if I am correct in going about it. The answer is not given, so I am having trouble figuring if I'm right or not.

Anyway, the question goes like this.

Saturated water mixture initially in a piston-cylinder device with a stopper.

Initial state: Volume, V1 = 0.00078539 m^3
Quality, x = 0.85
Pressure, P1 = 125 kPa

Heat is then introduced, after which the piston hits the stopper. The heating is continued until the pressure reaches 200 kPa.

Final state: Volume, V2 = 2Vi = 0.00157079
Pressure, P2 = 200 kPa

a) Find the initial temperature and mass of the liquid.

b) How is the final state, and what is its temperature?

The Attempt at a Solution


[/B]
a) I used the provided saturated water table, to find Tsat for P = 125 kPa, and got 105.97C.

For the mass of the liquid, I used x = (v1 - vf) / (vg - vf), where required values are retrieved from the table.

which gave v1 = 1.1689 m^3/kg

Mass of entire mixture, mt = V1/v1 = 0.00067191 kg

x = (mt - mL) / mt

mL = 0.00010078 kg

b) For the final state, I checked the saturated table for P = 200 kPa and found that the specific volume of the substance in question is more than that of saturated vapor at 200 kPa, so using that logic I deduced the final state to be superheated vapor.

v2 = V2 / mt

The temperature is then interpolated from the superheated vapor table at 200 kPa using the specific volume.

It was about 740 degrees celcius.

** Additional thought

Also, if the question required me to think about the state just as the piston hits the stopper, do I use P = 125 kPa, to find the specific volume and compare it with that in the saturated water table? So if v > v of gas --> superheated vapor?
 
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I checked your solution, and it is correct. As far as your additional thought is concerned, you don't have enough information. You do know the average specific volume when it hits the stopper, but you don't know what the temperature or the pressure is.

Chet
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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