What is Thevenin's Theorem and How Can It Help Simplify Complex Circuits?

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SUMMARY

The discussion focuses on Thevenin's Theorem and its application in simplifying complex circuits. Daniel, a newcomer to the forum, seeks clarification on a specific problem involving voltage division and resistor values. The solution involves using superposition and recognizing that the upper 2k Ohm resistor can be replaced by a short circuit, allowing for the calculation of Voc across the 12k Ohm resistor. This understanding is crucial for accurately applying Thevenin's Theorem in circuit analysis.

PREREQUISITES
  • Understanding of Thevenin's Theorem
  • Knowledge of voltage division in electrical circuits
  • Familiarity with superposition principle in circuit analysis
  • Basic concepts of resistors and their configurations
NEXT STEPS
  • Study Thevenin's Theorem applications in circuit simplification
  • Learn about voltage division and its mathematical formulation
  • Explore the superposition principle in more complex circuit scenarios
  • Review resistor configurations and their impact on circuit behavior
USEFUL FOR

Electrical engineering students, circuit designers, and anyone looking to deepen their understanding of circuit analysis techniques, particularly Thevenin's Theorem.

daniel.
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Homework Statement



[PLAIN]http://img21.imageshack.us/img21/2408/screenshot20101028at112.png

Hi,

I'm new to these forums, so hopefully this is the right place to post this question. I need some help in the question above. I'm not obtaining the right answer for this question and I'm not too sure whether my working out is correct as there there are no worked solutions for this question. If anyone can provide me some steps to solve this question, it will be greatly appreciated.

Thanks in advance.

Daniel
 
Last edited by a moderator:
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Okay, fortunately I've found the worked solutions for this question in my portal. But I still do not understand this part of the solution:

[PLAIN]http://img507.imageshack.us/img507/6680/screenshot20101028at115.png

I know that we are using superposition, but I do not understand how they got the values for the voltage division. Why is the 12k Ohm resistor used in the numerator? Like why does the voltage drop across the 12k ohm resistor equate to Voc'? And in the denominator, which 2k ohm resistor are they referring to? And why is the other 2k ohm ignored?

Thanks in advance
 
Last edited by a moderator:
There is no current through the upper 2k resistor, so no voltage drop. You can substitute it by a short circuit. In this way Voc is the voltage across the 12k resistor.
 
Thanks. Got it now.
 

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