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Ahhh! Thank you! I was able to transpose that equation for VTh and ended up with the answer I was expecting.
Thanks again.
Thanks again.
The discussion revolves around solving a homework problem related to Thevenin's Theorem, focusing on determining the load current in a circuit with a 50 Ω load fed by two voltage sources and their associated reactances. Participants explore various methods including Thevenin's theorem, superposition theorem, and Norton transformations, while addressing complexities introduced by reactance and power factor.
Participants generally agree on the need to apply Thevenin's theorem and other methods to solve for the load current, but there are multiple competing views on the correct approach to calculating impedance and voltage, as well as the interpretation of power factor. The discussion remains unresolved with participants expressing varying levels of understanding and confidence in their calculations.
Participants highlight limitations in their understanding of the circuit's behavior when the load is removed, the definitions of the voltage supplies, and the need for careful handling of complex arithmetic. There are also unresolved questions regarding the significance of different phase angles in the voltage sources.
I think you mean current source. You added the two Norton sources.Spongecake said:I am currently on part c) and have converted each voltage source and series impedance into a current source and parallel impedance using Ohms Law, I = V/Z which i get 103.75 for v1 and -J69.17 for v2.
Then combining them to get 103.75-j69.17 as my voltage source.
Yes, you're on the right track.Then to combine J4 and J6 which are in parallel which i make j2.4.
The next bit I'm slightly confused on which is to use current divider rule to calculate the load current which i think is Ix=[Rt/(Rt+Rx)]*It
It= the current source. Please can advise me if I'm on the right track.