Thickness of 304 stainless sheet to avoid puncture

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SUMMARY

The discussion focuses on determining the minimum thickness of a 304 stainless steel cylinder to prevent puncture from a 6-inch diameter steel bar dropped from a height of 1 meter. The cylinder's outer diameter is calculated to be 0.7512 meters, and the current wall thickness is 5 cm. Using the yield strength of Stainless Steel 304 at 206.8 MPa, the calculated stress on the cylinder wall is 488 MPa, which is below the ultimate tensile strength of 517.02 MPa for SS304, indicating that the design is structurally sound but may require further verification of assumptions.

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  • Familiarity with stress calculations in structural engineering.
  • Knowledge of basic geometry related to cylinder dimensions.
  • Experience with Stainless Steel 304 specifications and applications.
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  • Explore alternative materials or thicknesses for enhanced puncture resistance in design applications.
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Mechanical engineers, structural designers, and materials scientists involved in the design and analysis of load-bearing structures using Stainless Steel 304.

Nick P
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Designing a cylinder using Stainless Steel 304 and am trying to figure out the minimum thickness of the outer wall of the cylinder to avoid being puncture by a 6in diameter steel bar after falling 1 meter onto the bar.

Cylinder will weigh approximately 5500kg.
 
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What is the outer diameter of the cylinder?
 
0.7512 meters
 
What I have right now... is that

Syp,SS304=206.8MPa

F=π(.075m)2*206.8E6 = 3.66MN

and relating that to the current thickness we have at 5cm

σ=\frac{3.66MN}{.15m*.05m}=488MPa

And 488MPa < Sut,SS304 with Sut,SS304=517.02MPa

But I'm pretty positive I'm making some logical error here.
 

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