Thin ring rolling down a moving ramp

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Homework Statement


A pipe(thin ring)has a mass of 500kg and radius of 0.5m and rolls without slipping down a 300kg ramp. If the ramp is free to move horizontally(frictionless, determine the acceleration of the ramp. (angle of ramp is 30 degrees)


Homework Equations


Fs (static friction) = Resultant torque
Linear conservation of momentum(in horizontal axis)


The Attempt at a Solution



I am trying to get the acceleration of the ramp, i found the acceleration of the pipe using Principle of Angular momentum and I got Ap = 2.4525.

I then used the linear conservation of momentum which is 0 = (Vpcos30 - Vramp)i
then i differentiated both sides to get 0.866Ap - Aramp = 0 (cos30 = 0.866) which I then used to attempt to get Aramp. But my answer turned out to be wrong. What am i doing wrong here? any help? the solution in my book is Aramp = 1.7336
 
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hi darkdraggy! welcome to pf! :smile:
darkdraggy said:
I then used the linear conservation of momentum which is 0 = (Vpcos30 - Vramp)i

erm :redface:

masses! :wink:
 
hello! i did use them in my equation but i did not get a correct answer.

help anyone please? :(
 
Last edited:
darkdraggy said:
hello! i did use them in my equation but i did not get a correct answer.

help anyone please? :(


anybody can help?