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Hi. I'm having a dickens of a time coming up with the correct answer for this.

I shall describe the question as it includes an image. There are three blocks altogether, b_1, b_2, b_3, each with a mass m_1, m_2, and m_3, respectively, and the blocks are all connected together by two ropes, T_1 between b_1 and b_2, and T_2 between b_2 and b_3. Blocks b_1 and b_3 are hanging from a pulley at the end an incline that has an angle of theta degrees (going up from left to right, b_1 on the left, b_3 on the right) and on this incline is b_2 which has a friction coefficient mu.

I've set it up a bunch of different ways but have not found the correct solution. Here is the last version:

m_1 g - T_1 = m_1 a

T_1 + sin(theta) m_2 g - mu cos(theta) m_2 g - T_2 = m_2 a

T_2 - m_3 g = - m_3 a (*)

For *, This was the last attempt to I made the acceleration negative (I tried it positive before).

Any help would be greatly appreciated!! Thanx, lizzy

I shall describe the question as it includes an image. There are three blocks altogether, b_1, b_2, b_3, each with a mass m_1, m_2, and m_3, respectively, and the blocks are all connected together by two ropes, T_1 between b_1 and b_2, and T_2 between b_2 and b_3. Blocks b_1 and b_3 are hanging from a pulley at the end an incline that has an angle of theta degrees (going up from left to right, b_1 on the left, b_3 on the right) and on this incline is b_2 which has a friction coefficient mu.

I've set it up a bunch of different ways but have not found the correct solution. Here is the last version:

m_1 g - T_1 = m_1 a

T_1 + sin(theta) m_2 g - mu cos(theta) m_2 g - T_2 = m_2 a

T_2 - m_3 g = - m_3 a (*)

For *, This was the last attempt to I made the acceleration negative (I tried it positive before).

Any help would be greatly appreciated!! Thanx, lizzy

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