Question: A particle of charge 4.96 nC is placed at the origin of an xy-coordinate system, and a second particle of charge -1.95 nC is placed on the positive x-axis at x = 3.99 cm. A third particle, of charge 6.04 nC is now placed at the point x = 3.99 cm, y = 3.05 cm. Part A Find the x-component of the total force exerted on the third charge by the other two. Use 8.85 * 10^(−12) C^2/(N*m^2)for the permittivity of free space. I drew the first quadrant of an xy-plane and labeled the three particles. The force of one on three is 8.99*10^9)(4.96*10^(-9))(6.04\cdot10^(-9))/(.0502^2). which equals 1.07*10^(-4) N. The x-component for this is 1.07*10^(-4)*(3.99)/(5.02). I believe there is no x-component for the second particle. Am I right? I couldn't get the LaTeX to work, I apologize for that.