1. The problem statement, all variables and given/known data Three charges, q1 = 8.43nC, q2 = -4.29nC and q3 = 3.00nC are at the corners of an equilateral triangle, as shown in the figure below. A. The angle alpha is 60.0° and L = 0.448 m. We are interested in the point midway between the charges q1 and q2 on the x axis. For starters, calculate the magnitude of the electric field due only to charge q3 at this point. B. Now calculate the magnitude of the electric field from all three charges at a point midway between the two charges on the x axis. C. Calculate the angle of the electric field relative to the positive (to the right) x-axis, with positive values up (Counter-Clock Wise) and negative down (Clockwise). (enter the answer with units of deg) D. If a tiny particle with a charge q= 1.41nC were placed at this point midway between q1 and q2, what is the magnitude of the force it would feel? 2. Relevant equations W=Fdcosθ=(qE)dcosθ lFl= (1/4 pie r^3)* (lq1l lq2l/r^2) 3. The attempt at a solution A. (8.99E9)((3E-6)^2)=.08091 Then i found the distance from 3 to the midpoint. .224tan60=.387 .08091/.387=.209N/C B. (8.99E9)((8.43E-6)(4.29E-6)(3E-6)/.224^2)=1.95E-5 C. An equilateral triangle is 180 degress and each angle is 60 I am so confused, any help would be greatly appreciated.