MHB Three Consecutive Odd Integers

[mathdad]

Find three consecutive odd integers such that the square of the first plus the square of the third is 170.

See picture for the set up.

View attachment 7356

Is the set up correct?

 

[topsquark]

Re: Three Executive Odd Integers

Find three consecutive odd integers such that the square of the first plus the square of the third is 170.

See picture for the set up.

Is the set up correct?

That's good. Just solve for x and make sure your answer is odd. Another addition to this would be to set x = 2n + 1, which forces x to be odd, but you don't actually have to take this step.

-Dan

Edit: Whoops! Your equation should only contain two numbers: [math]x^2 + (x + 4)^2 = 170[/math]. Sorry about that.

 

[mathdad]

Re: Three Executive Odd Integers

That's good. Just solve for x and make sure your answer is odd. Another addition to this would be to set x = 2n + 1, which forces x to be odd, but you don't actually have to take this step.

-Dan

Edit: Whoops! Your equation should only contain two numbers: [math]x^2 + (x + 4)^2 = 170[/math]. Sorry about that.

Ok. Thanks.

 

[mathdad]

Re: Three Executive Odd Integers

See picture reply.

View attachment 7357

Correct?

 

[topsquark]

Re: Three Executive Odd Integers

See picture reply.

Correct?

You switched signs. It's [math](x - 7)(x + 11) = x^2 + (-7 + 11)x - 77 = x^2 + 4x - 77[/math].

-Dan

 

[mathdad]

Re: Three Executive Odd Integers

I rushed through the problem. Thanks for the correction.

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