Three dielectric slabs in a capacitor

[gracy]

If dielectrics partition the space horizontally , they are in series and if dielectrics partition the space vertically then they are parallel. Correct?

And the direction of given capacitor plates is always considered to be horizontal. Right?

 

[cnh1995]

And the direction of given capacitor plates is always considered to be horizontal. Right?

Yes.

 

[gracy]

given capacitor plates

The plate which are at extreme positions i.e the left and right most.

 

[cnh1995]

The plate which are at extreme positions i.e the left and right most.

If the partition is parallel to the plates, they're in series and if the partition is perpendicular to the plates, they're in parallel.

 

[gracy]

If the partition is parallel to the plates, they're in series and if the partition is perpendicular to the plates, they're in parallel.

Any exceptions?

 

[cnh1995]

Any exceptions?

None. But the partitions should be continuous from one end to the other.

 

[gracy]

But the partions should be continuous from one end to the other.

You mean there should not be empty space in between ?

 

[cnh1995]

I meant something like this..

 

[gracy]

The two plates of parallel capacitors should have same area . Is that correct?

 

[cnh1995]

The two plates of parallel capacitors should have same area . Is that correct?

What do you mean by "two plates"? Which two plates?

 

[gracy]

http://astarmathsandphysics.com/university-physics/electricity-and-magnetism/parallel-plate-capacitors-html-9fd61e5.gif

Here the two plates have same area "A" ,I want to ask what if they had different areas , will they still form parallel plate capacitors together?

 

[cnh1995]

http://astarmathsandphysics.com/university-physics/electricity-and-magnetism/parallel-plate-capacitors-html-9fd61e5.gif

Here the two plates have same area "A" ,I want to ask what if they had different areas , will they still form parallel plate capacitors together?

Yes. But the capacitance will be different.

 

[gracy]

What will we write in place of A in the below formula ? A or B?
$\frac{Aε0}{d}$ If one plate has area "A" and the other "B"

 

[cnh1995]

The charges have to be uniformly distributed on both the plates and the plates have different areas. I believe the capacitance calculation will be a little complicated.

 

[gracy]

Ok. What will be the formula of capacitance for the plate 2 here

 

[cnh1995]

What are those blue portions? Dielectrics? What are the red lines joining them? Wires?

 

[gracy]

What are those blue portions? Dielectrics? What are the red lines joining them? Wires?

Yes and yes.

 

[cnh1995]

Given the area, separation and permitivitty, its capacitance would be C=Aε/d..

 

[gracy]

A is area of ? And why there isn't "K" present?

 

[cnh1995]

A is area of ? And why there isn't "K" present?

What's the need of k when there is 'ε' which is itself kε_o? A is the area of each plate(which is same throughout). I don't understand why you are analyzing this diagram.

 

[gracy]

Ok. Fine. Let's end this thread here as it is going off topic.