Three inductors in series , of increasing inductance

In summary: The total inductance limits the AC current (as you know). AC losses and wire resistance contribute to the heating in the series circuit. The amount of heating in each depends on how you wind the inductors, the size of the cores, the geometry of the cores, the core material, etc. If you only vary the number of turns to make the different inductances on identical cores, then yes, the largest inductor will heat the most. However, in your example, you probably wouldn't use the same core to make the 3 inductors that vary in inductance by 2 orders of magnitude.
  • #1
B0b-A
155
32
three inductors in-series, of increasing inductance , say 1μH , 10μH and 100μH , wire-gauge constant and wire has some resistance which is constant per unit length.

Is it possible to make the middle inductor, (10uH), the hottest of the three by adjusting the frequency of the AC passing through this series circuit ? , [ i.e. via a resonant, "tuning" effect ].

or will the biggest inductor (100μH) always be the hottest of the three regardless of the frequency of the AC in this series circuit ?
 
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  • #2
B0b-A said:
three inductors in-series, of increasing inductance , say 1μH , 10μH and 100μH , wire-gauge constant and wire has some resistance which is constant per unit length.

Is it possible to make the middle inductor, (10uH), the hottest of the three by adjusting the frequency of the AC passing through this series circuit ? , [ i.e. via a resonant, "tuning" effect ].

or will the biggest inductor (100μH) always be the hottest of the three regardless of the frequency of the AC in this series circuit ?

Why do you want the inductors to get hot?
 
  • #3
The only thing that causes heat is the resistance of the coil. Even if all the inductors have the same wire gauge (ohms per meter) it doesn't necessarily mean that the inductance is proportional to the wire length. Inductance can also be affected by the diameter of the coil, the type of core, the current through the coil (higher currents can saturate the core reducing the inductance) and even how the coil is wound.
 
  • #4
berkeman said:
Why do you want the inductors to get hot?

The heating was an unintentional side-effect.
skeptic2 said:
The only thing that causes heat is the resistance of the coil.

If the coils were in parallel that wouldn't be true : at high AC frequencies there would be less current through the larger inductor because of its larger inductive-reactance , [ like a "choke" ]. Less current means less ohmic heating.

However in the case I outlined the coils are in series, not parallel.
 
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  • #5
B0b-A said:
If the coils were in parallel that wouldn't be true : at high AC frequencies there would be less current through the larger inductor because of its larger inductive-reactance , [ like a "choke" ]. Less current means less ohmic heating.

However in the case I outlined the coils are in series, not parallel.

Yes, you asked about a series combination, and that is what skeptic2 replied about. The only additional heating effects beyond what he mentioned are AC losses (from eddy currents and other effects).

Can you provide some context to your question? What are you trying to do?

Also, keep in mind that inductors in close proximity can also share flux, which alters their inductance...
 
  • #6
berkeman said:
Yes, you asked about a series combination, and that is what skeptic2 replied about. The only additional heating effects beyond what he mentioned are AC losses (from eddy currents and other effects).

Can you provide some context to your question? What are you trying to do?

I was reviewing someone else's design for an experiment which had three coils in series with an alternating current , and the assumption was that any heating would be greatest on the largest inductor, (with the largest number of windings).

If the coils were in parallel that would not be the case : at high frequencies of AC the current to the largest inductor would be choked and any ohmic heating would be reduced because of the reduced current.

I wasn't certain that similar frequency-depended behaviour couldn't happen in a series arrangement , which is what prompted the question.
 
  • #7
B0b-A said:
I was reviewing someone else's design for an experiment which had three coils in series with an alternating current , and the assumption was that any heating would be greatest on the largest inductor, (with the largest number of windings).

If the coils were in parallel that would not be the case : at high frequencies of AC the current to the largest inductor would be choked and any ohmic heating would be reduced because of the reduced current.

I wasn't certain that similar frequency-depended behaviour couldn't happen in a series arrangement , which is what prompted the question.

The total inductance limits the AC current (as you know). AC losses and wire resistance contribute to the heating in the series circuit. The amount of heating in each depends on how you wind the inductors, the size of the cores, the geometry of the cores, the core material, etc. If you only vary the number of turns to make the different inductances on identical cores, then yes, the largest inductor will heat the most.

In your example, though, you probably wouldn't use the same core to make the 3 inductors that vary in inductance by 2 orders of magnitude.

Quiz Question -- how does the inductance vary with the number of turns?
 
  • #8
berkeman said:
Quiz Question -- how does the inductance vary with the number of turns?
(Number of turns)^2Back to the original question ... What if stray-capacitance is added , (see attachment) ,
could that cause the middle coil to become the hottest at some resonant-frequency ?

attachment.php?attachmentid=70349&d=1401945844.png
 

Attachments

  • series coils, now with stray capacitance.png
    series coils, now with stray capacitance.png
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  • #10
If C2 is a tiny capacitor and C1 and C3 are large capacitors the the currents through the inductors would not be equal.

On the other hand, Assuming the capacitors are reasonable parasitic values, Power factor will cause some variation, won't it? Any AC guy care to work that out?
 
  • #11
The keyword for me was parasitic. IMO, the parasitic capacitances won't change the situation.
 
  • #12
But the mutual inductances would change the situation if the inductors were stacked end-to-end.

Quiz Question -- if the inductor slugs were stacked end-to-end, how would that change the heating situation?
 
  • #13
RE Quiz: are all the windings in the same direction?
 

What is the total inductance of three inductors in series?

The total inductance of three inductors in series is equal to the sum of their individual inductances. This can be calculated using the formula: L_total = L1 + L2 + L3.

How does the inductance change when the inductors are connected in series?

When inductors are connected in series, the total inductance increases. This is because the magnetic fields produced by each inductor combine, resulting in a stronger overall magnetic field and thus a higher inductance.

What happens to the current when inductors are connected in series?

The current remains the same in all the inductors when they are connected in series. This is because, according to Kirchhoff's Voltage Law, the sum of the voltage drops across each inductor must equal the total voltage of the circuit. Therefore, the same current must flow through each inductor.

Can the inductance of the individual inductors affect the total inductance in a series circuit?

Yes, the inductance of each individual inductor does affect the total inductance in a series circuit. The greater the inductance of each inductor, the higher the total inductance will be. This is because, as mentioned earlier, the magnetic fields combine to produce a stronger overall magnetic field.

What happens to the resistance of the circuit when inductors are connected in series?

The total resistance of the circuit increases when inductors are connected in series. This is because the inductive reactance (XL) of each inductor adds up, resulting in a higher overall impedance. This can be calculated using the formula: Z_total = √(R^2 + (XL1 + XL2 + XL3)^2).

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