I wired a capacitor in series with a 4 ohm tweeter speaker to serve as a high-pass filter. I used the capacitive reactance equation to figure my capacitor value to filter the speaker at 2.2khz.(adsbygoogle = window.adsbygoogle || []).push({});

X_{c}=1/2PiFC

4=1/2Pi(2200)C

Solve for C and you get .00001809 Farads or 18uF.

And?

It sounds like something you'd buy from one of those big box stores. It sounds terrible. I'm running out of x-max on the tweeter & it's distorting at higher volumes. I want to turn my mediocre 1st order crossover into a 2nd order filter so I don't burn out the voice coil & destroy my tweeters. So, toss an inductor across the terminals of the speaker. That's the issue though. I don't know how to integrate (not literally) the inductive reactance equation...

Can I just simply plug in 2200 for frequency, 4 for X_{l}, & solve for L?

.32mH

I'm asking because I'm not sure if the capacative/inductive reactance equations only apply when the capacitor or inductors are in series with the load. The inductor is "shunting" to ground here so...

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# Capacitive/inductive reactance in a series-parallel circuit

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