- #1

Rugile

- 79

- 1

## Homework Statement

There are three parallel identical planes of area A = 200 cm^2, and the distance between the upper and the middle one as well as the distance between the middle and the lower one is d = 3cm. The upper plane was charged to q1 = 0.5 nC. The other two were connected to a V= 100V EMF source. Calculate the charges of the middle and lower planes.

## Homework Equations

[itex] V = E * d [/itex]

[itex] E * A = q / \epsilon_0 [/itex]

## The Attempt at a Solution

I firstly assumed that after being connected to the source, the potential of the middle plane is 0 V, and the potential of the lower plane - 100V. Then from Gaus's law, we find the electric field between the planes:

[itex] E_{12} * A = \frac{q_1 + q_2}{\epsilon_0} [/itex]

[itex] E_{23} * A = \frac{q_2 + q_3}{\epsilon_0} [/itex]

Where 1st, 2nd and 3rd planes are upper, middle and lower correspondingly.

Then

[itex] V_{12} = E_{12}*d = \frac{(q_1 + q_2)*d}{\epsilon_0 * A} [/itex]

[itex] V_{23} = 100 = E_{23}*d = \frac{(q_2 + q_3)*d}{\epsilon_0 * A} [/itex]

But here we have 3 unknowns and 2 equations... Are there any other ways to calculate [itex]V_{12} [/itex], for instance?