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I Ti:sapphire: laser propagation

  1. Jan 18, 2017 #1
    Hello :)

    I have 2 questions about the beam propagation of an Ti:sapphire-laser:

    Picture 1: The cw argon ion laser brings the beam to mirror (1). Then...? Then the beam (100% of it), go to the birefringent plate (4), gets then reflectet to the first mirror again (1) , which reflects it to the Ti:sapphire, then to mirror (2) , which brings the beam to the last mirror, that which is responsible for the outcoppling.!?!

    But thats propably not right, because the birefringent plate is responsible for wavelength tuning. Because the resulting Laserbeam doesn`t "meet" this plate.

    Picture 2: Ti:sapphire: femtosecond-laser. Here the same: what happens at mirror (2)? or is the birefringent plate useful for wavelength tuning of the pumping-laser, and not the resulting Laserbeam? And on this picture I miss the outcoppling beam...

    Thank you for your help :)

    Attached Files:

  2. jcsd
  3. Jan 18, 2017 #2


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    Staff: Mentor

    I'm not an experimentalist, but my understanding of this is as follows. The Brewster plate is not a filter, what it does is that it changes the properties of the entire cavity (made up of all the mirrors). Its setting will determine for which frequency there will be constructive interference (which frequency will "fit" inside the cavity). Therefore, it doesn't matter that it is not in the leg where the outcoupling occurs.
  4. Jan 18, 2017 #3
    So I have to think about an standing wave which occurs between mirrors 1, 2, 3 and 4? (Because the entire cavity is made of all the mirrors). And the birefringent plate "choses" the waves, which can build up such a standing wave. (Results out of destructive and constructive interference).!?

    Thank you :)

    And on second picture the same. Just that mirror (5) is not 100% reflecting, so that a beam is coupled out there.?!
  5. Jan 19, 2017 #4

    Andy Resnick

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    Education Advisor

    Figure 1 is a bit unclear (no legend, for example). It seems that it corresponds to mode locked (pulsed) output. My understanding is that the pump beam propagates through the Ti:Saph crystal and then exits the cavity. Ti:Saph output pulses circulate through the x-cavity as: 1 -> 2 ->3 -> 2 ->1 -> 4 ->1 ->2 etc.. Mirror 3 is the output coupler, the pump beam does not circulate through the cavity. I am unclear about the function of the tuning plate, my guess is that it's required because Ti:Saph is birefringent, so a compensating plate is needed to control the phase matching of pulses as they circulate.

    Figure 2 is very similar to figure 1, the addition of GVD correction (the prism pair) permits the generation of fs pulses. Again, the tuning plate may be required because of the intrinsic Ti:Saph birefringence. Apparently one can omit the tuning plate by rotating the Ti:Saph crystal:

    https://www.researchgate.net/publication/26265365_Wavelength_tuning_of_Titanium_Sapphire_Laser_by_its_own_crystal_birefringence [Broken]

    Does this help?
    Last edited by a moderator: May 8, 2017
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