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1. The problem statement, all variables and given/known data

A spaceship is moving at 0.75 c (0.75 times the speed of light) with respect to the earth. An observer on the spaceship measures the time interval between two events on earth as 38 hrs. If the spaceship had been moving with a speed of 0.92 c with respect to the earth, what would the time interval between the events have been?

Δt0.92 c = _____hrs

2. Relevant equations

Δt=Δtp/sqrt1-v^2/c^2

3. The attempt at a solution

v=.75(3e8)=2.25e8m/s

t=1/368e5sec

v=d/t

d=3.078e13m

Δtp=3.078e13/v

v=.92(3e8)=2.76e8

Δtp=3.078e13/2.76e8

=1.115e5sec

=30.97hr

but this is not the correct ans

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# Homework Help: Time Dilation help

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