phyti
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Assume a clock runs at the same rate independently of its speed. Clock A moving at a constant speed of .6c and clock B moving at a constant speed of .8c, travel a straight line distance of 12 light sec. Starting at t=0, at the finish line, A reads 20 sec, B reads 15 sec. Since t=x/v, an inverse relation of t to v, the faster clock reads less time than the slower clock. Applying SR corrections, the difference is even greater. The confusion of longer line, shorter time, results from interpreting the Minkowski graphic as a 2D geometric road map, which it is not.stevendaryl said:For the Euclidean analogy, the curved path is longer (in spatial distance). For the Minkowsky case, the "curved" path is shorter (in proper time).
Let me try another analogy: Suppose you have a rubber tube of length 10 inches. You stuff it into a box that is only 5 inches long. Then you can prove that it's necessary to bend the tube to get it to fit into the box. But it would be weird to say that bending the tube is what made it 10 inches long. Saying that accelerating a clock makes its path shorter (in proper time) seems exactly analogous to saying that bending a tube makes it longer.(in spatial distance).
What bending the tube does is to allow a 10 inch tube to fit into a 5 inch box.