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Time evolution of a particle in an ISW after the well

  1. Apr 12, 2013 #1
    1. The problem statement, all variables and given/known data

    How does the state of a particle in an ISW evolve with time after the width of the well doubles - from a to 2a
    If the particle starts in the ground state of the half width well, then immediately after the well doubles it will be undisturbed therefore the initial wave function is
    |P(0)>=Integrate[Sqrt[2/a] Sin[3.1415... x/a], {x,0,a}] |x>
    THe evolution operator is
    |P(t)>=Exp[-i E t/hbar] |P(0)>
    2. Relevant equations



    3. The attempt at a solution
    Does this mean that the solution is just stitching those two equations together? I plotted it and it came out that the solution just went up and down in the half well (or, if I changed the integration limits, it came out at just the second excited state of the full well).
    I was under the impression that some sort of spreading had to occur, but I'm not sure how to get it...
     
    Last edited: Apr 12, 2013
  2. jcsd
  3. Apr 12, 2013 #2

    TSny

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    What are the new energy eigenstate wavefunctions for the expanded well? These become the states that have a simple time evolution.

    [EDIT: I don't understand this expression: |P(0)>=Integrate[Sqrt[2/a] Sin[3.1415... x/a], {x,0,a}] |x>]
     
    Last edited: Apr 12, 2013
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