Time needed for a Force F to accelerate the crate to 2m/s? (Dynamics)

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SUMMARY

The discussion centers on calculating the time required for a force to accelerate a crate to a velocity of 2 m/s up an incline. The correct answer, as confirmed by the book, is T=1.929 seconds. A participant initially miscalculated by equating the entire equation to zero instead of the target velocity, 2 m/s. This highlights the importance of correctly setting equations in dynamics problems to achieve accurate results.

PREREQUISITES
  • Understanding of Newton's Second Law of Motion
  • Familiarity with kinematic equations
  • Basic knowledge of forces acting on inclined planes
  • Ability to manipulate algebraic equations
NEXT STEPS
  • Study the application of Newton's Second Law in dynamics problems
  • Learn about kinematic equations and their derivations
  • Explore forces on inclined planes and friction effects
  • Practice solving dynamics problems with varying initial conditions
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone involved in mechanics or dynamics, particularly those focusing on force and motion analysis.

bardia sepehrnia
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Homework Statement
The mass of the crate, coefficient of static and kinetic friction is given. The force equation is also given.
Relevant Equations
F=300t
242317

So above is the question. The picture below is my attempt at the solution:
242318


However the answer at the back of the book suggest that T=1.929s
 
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I agree with the book. What did you do at the very last step? What does v=1.292 mean and how did you get it? You are supposed to find the time when the velocity is 2 m/s up the incline.
 
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kuruman said:
I agree with the book. What did you do at the very last step? What does v=1.292 mean and how did you get it? You are supposed to find the time when the velocity is 2 m/s up the incline.
Wow, I've been doing dynamics for too long today and been extremely tired and frustrated. For some reason I equated the entire equation to 0 where as you pointed out, I obviously had to equate it to 2. Thank you very much!
 

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